Which correct command set configures HSRP for VLAN 1200 with the last usable subnet IP as the virtual address?

350-401 By islever Editorial Last updated

Short answer

B SW1(config)# interface vlan 1200

Question

An engineer must configure HSRP for VLAN 1200 on SW1. The second switch is configured by using the last usable IP address in the network as the virtual IP. Which command set accomplishes this task?
  1. SW1(config)# interface vlan 1200
  2. SW1(config)# interface vlan 1200 Correct Answer
  3. SW1(config)# interface vlan 1200
  4. SW1(config)# interface vlan 1200

Key Takeaways

HSRP v1 only supports group numbers 0-255; group 1200 requires HSRP v2, paired with the subnet's last usable IP as the virtual address.

This question tests the mandatory configuration rules for HSRP group 1200 on VLAN 1200, including version requirements and correct virtual IP assignment.

Common mistake: Many candidates incorrectly select Option C, ignoring that group 1200 exceeds HSRP v1's 0-255 range and will trigger a configuration error.

Expert Analysis

Correct Option Justification

  • Option B is fully compliant with Cisco HSRP specifications. It enables HSRP version 2 on the VLAN 1200 SVI, which supports group numbers up to 4095, and assigns the last usable IP of the subnet (172.12.0.254 for a /24 network) as the valid virtual HSRP address, meeting all task requirements.

Incorrect Option Analysis

  • Option A: It uses the default HSRP v1, which cannot support group 1200, and fails to set the required last usable IP as the virtual address.
  • Option C: It relies on default HSRP v1, which cannot recognize group 1200 and will throw a PT error during configuration, making it non-functional.
  • Option D: It uses default HSRP v1 that does not support group 1200, and includes unnecessary extra configurations not required by the task.

Related Technical Principle

Cisco HSRP version 1 uses IPv4 multicast address 224.0.0.2 and only supports 256 total groups (0-255). HSRP version 2 expands the group number range to 0-4095, aligning with VLAN ID ranges, uses multicast 224.0.0.102, and fixes the group number conflict issue for VLAN-aware deployments.

Exam Strategy

Check if the HSRP group number exceeds 255 first, confirm HSRP v2 is enabled, then verify the last usable virtual IP.

Community Votes

B
95%
C
5%

95% of anonymous learners picked answer B. Votes are pick records left by other test-takers — they are not the verified answer.

Discussion 7 contributions

Compiled from public community threads and reader submissions, lightly edited for clarity. Handles and vote tallies are shown as recorded, and comments reflect the views of individual contributors.

From public community threads 7

  1. shefo1 👍 14 Answered B
    because we use the group number 1200 , we must configure HSRP version 2 , if we dont do that , we receive this error : Switch(config-if)#standby 1200 ip 172.12.0.254 PT ERROR: HSRP version 2 is required for specified group number -- so the option C and D is wrong -- and A is wrong because he doesn't use last usable IP address for virtual IP
  2. EAC84 👍 6
    The standby group number= The default is 0. The group number range is from 0 to 255 for HSRP version 1 and from 0 to 4095 for HSRP version 2. need to specify "standby version 2" in order to assign group number 1200
  3. [Removed] 👍 1 Answered B
    B is correct no need for timers or preemption stick to the question, you were asked to just configure HSRP with a virtual IP "the last available in the subnet" so find the option with the correct addressing and the fewer extra configuration
  4. AbdullahMohammad251 👍 1 Answered B
    HSRP group number is greater than 255, version 2 must be used. The virtual IP address is configured to be the last usable IP in the subnet (172.12.0.0/24) = 172.12.0.254/24
  5. chmacnp 👍 1 Answered B
    B due to HSRP group 1200. HSRPv2 allows for 4095 groups as opposed to HSRPv1 which allows for 255
Show 2 more comments
  1. ExamTaker1017 👍 1 Answered B
    Version 2 needed for vlans 0-4095 Virtual IP needs to be last in subnet (.254)
  2. leehyoeun 👍 1 Answered C
    answer is c

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