Electing the Root Bridge in PVST+ by Priority and MAC
Refer to the exhibit. Which switch in this configuration will be elected as the root bridge? SW1 0С:0A:05:22:05:97 - SW2 0С:4A:82:07:57:58 - SW3 0C:0A:A8:1A:3C:9D - SW4 0С:0A:18:A1:B3:19 - 
Community Votes
71% of anonymous learners picked answer D. Votes are pick records left by other test-takers — they are not the verified answer.
Community Insight
Priority is compared before MAC. Even though SW1's MAC (0C:0A:05...) is numerically lowest, its default priority 32768 loses to SW3/SW4's 8192, so MAC only breaks the tie between those two.
STP/PVST+ elects the root bridge by the lowest bridge priority, then by the lowest MAC address as a tiebreaker. SW3 and SW4 share priority 8192 (lower than the 32768 default on SW1/SW2), and SW4's MAC is lower than SW3's, so SW4 becomes root.
Picking SW1 because its MAC looks lowest, or SW3 without comparing the MAC tiebreaker. Always apply priority first, then MAC within the same priority.
Community Discussion (7 comments)
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Expert Analysis
Why the Answer Is Correct
D (SW4) is correct. Root election compares bridge priority first: SW3 and SW4 both run priority 8192, lower than SW1/SW2's default 32768. With priority tied, the lower MAC wins — SW4 (0C:0A:18:A1:B3:19) is lower than SW3 (0C:0A:A8:1A:3C:9D), so SW4 is root.Why the Other Options Are Wrong
A (SW1) and B (SW2) have the higher default priority 32768, so they cannot win. C (SW3) loses the MAC tiebreaker to SW4 despite sharing the lowest priority.Community Comment Notes
Detailed comments (71 votes for D) confirm: SW3 and SW4 have lowest priority 8192, and SW4's MAC is lower, so SW4 is root. A few comments mistakenly pick SW3 by stopping after priority.Official Reference
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