Forming the EUI-64 Suffix for Router R1 (Segment 8)
Short answer
C Applying EUI-64 to R1's MAC yields 2001:db8:8bb3:8bb1:C801:B8FF:FEB3:1.
Question

Key Takeaways
Same pattern: C8 from the flipped bit and the FFFE marker (B8FF) identify the correct option C.
EUI-64 on R1's MAC: invert the seventh bit to C8 (C801), insert FFFE (B8FF), and append the host half to produce FEB3, matching option C.
Common mistake: Picking A/B (C001/C081 miss the inversion) or D (no FFFE/inversion present).
Expert Analysis
Why the Answer Is Correct
C is correct. EUI-64 on R1's MAC: the first byte CA flips its seventh bit to C8, so the interface ID starts with C801, and the FFFE insertion gives B8FF, yielding 2001:db8:8bb3:8bb1:C801:B8FF:FEB3:1.
Why the Other Options Are Wrong
A (C001) and B (C081) miss the seventh-bit inversion. D does not follow the EUI-64 transformation of the exhibited MAC.
Community Comment Notes
The vote is C (100). Commenters derive CA -> C8 and confirm C801:B8FF as the resulting form.
Official Reference
https://learningnetwork.cisco.com/s/ccna-exam-topics
This link opens the official vendor documentation in a new tab.
Community Votes
100% of anonymous learners picked answer C. Votes are pick records left by other test-takers — they are not the verified answer.
Discussion 5 contributions
Compiled from public community threads and reader submissions, lightly edited for clarity. Handles and vote tallies are shown as recorded, and comments reflect the views of individual contributors.
From public community threads 5
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kitannnnn 👍 2 Answered Cca = 11001010 inverted 7th bit = 11001000 = c8 ans = c801:b6ff:feb4:0001
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ekansh_m 👍 2 Answered CCorrect answer is C
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Ras_Al_Ghul 👍 1 Answered Cconvert 7th bit ca becomes c8
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6353e2d 👍 1C is the correct answer
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exiledwl 👍 1 Answered CC is correct
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