Forming the EUI-64 Suffix for Router R1 (Segment 8)

Answer Correct answer: C — Applying EUI-64 to R1's MAC yields 2001:db8:8bb3:8bb1:C801:B8FF:FEB3:1.

Refer to the exhibit. The IPv6 address for the LAN segment on router R1 must be configured using the EUI-64 format. When configured which ipv6 address is produced by the router? - image

  1. 2001:db8:8bb3:8bb1:C001:8BFE:FF31:1
  2. 2001:db8:8bb3:8bb1:C081:B8FF:FF3B:1
  3. 2001:db8:8bb3:8bb1:C801:B8FF:FEB3:1 Correct Answer
  4. 2001:db8:8bb3:8bb4:7397:79FF:EF41:1

Community Votes

C
100%

100% of anonymous learners picked answer C. Votes are pick records left by other test-takers — they are not the verified answer.

Community Insight

Same pattern: C8 from the flipped bit and the FFFE marker (B8FF) identify the correct option C.

EUI-64 on R1's MAC: invert the seventh bit to C8 (C801), insert FFFE (B8FF), and append the host half to produce FEB3, matching option C.

Picking A/B (C001/C081 miss the inversion) or D (no FFFE/inversion present).

Community Discussion (6 comments)

exiledwl 👍 1 Selected: C
C is correct
98c965f 👍 1 Selected: C
C is correct
6353e2d 👍 1
C is the correct answer
kitannnnn 👍 2 Selected: C
ca = 11001010 inverted 7th bit = 11001000 = c8 ans = c801:b6ff:feb4:0001
Ras_Al_Ghul 👍 1 Selected: C
convert 7th bit ca becomes c8
ekansh_m 👍 2 Selected: C
Correct answer is C

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Expert Analysis

Why the Answer Is Correct

C is correct. EUI-64 on R1's MAC: the first byte CA flips its seventh bit to C8, so the interface ID starts with C801, and the FFFE insertion gives B8FF, yielding 2001:db8:8bb3:8bb1:C801:B8FF:FEB3:1.

Why the Other Options Are Wrong

A (C001) and B (C081) miss the seventh-bit inversion. D does not follow the EUI-64 transformation of the exhibited MAC.

Community Comment Notes

The vote is C (100). Commenters derive CA -> C8 and confirm C801:B8FF as the resulting form.

Official Reference

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