EUI-64 Interface ID Calculation for Router R2 (Segment 7)

Configure and verify IPv6 addressing and prefix
Answer Correct answer: A — Applying EUI-64 to R2's MAC yields 2001:db8:9bb6:6bb9:C801:B6FF:FEB4:1.

Refer to the exhibit. The IPv6 address for the LAN segment on router R2 must be configured using the EUI-64 format. When configured which ipv6 address is produced by the router? - image

  1. 2001:db8:9bb6:6bb9:C801:B6FF:FEB4:1 Correct Answer
  2. 2001:db8:9bb6:6bb9:C001:6BFE:FF01:1
  3. 2001:db8:9bb6:6bb9:C081:B6FF:FF4B:1
  4. 2001:db8:9bb6:6bb9:4736:931F:FE37:1

Community Votes

A
100%

100% of anonymous learners picked answer A. Votes are pick records left by other test-takers — they are not the verified answer.

Community Insight

Consistent with the bank's EUI-64 questions: the answer shows C8 (inverted bit) and the FFFE position (B6FF). A is the only option with both.

EUI-64: split the MAC, insert FFFE, and invert the seventh bit. R2's first byte becomes C8, giving C801; the FFFE insertion gives B6FF; the host half completes to FEB4, matching option A.

Picking B/C (C001/C081 miss the inversion) or D (no FFFE/inversion present).

Community Discussion (8 comments)

exiledwl 👍 2 Selected: A
With the number of times we've seen this exact question in the bank, we better get it at least once on exam
exiledwl 👍 1 Selected: A
A is right
bezkin 👍 1 Selected: A
remember 7th bit For Figuring Fast Eui64 (7th bit FFFE)
cybercerberes 👍 1 Selected: A
Add FF:FE beetwen B6 B4 in this case and you find IPv6 EUI-64
Blumen 👍 1 Selected: A
CA - 1100 1010 Invert 7th bit => 1100 1000 => C8 Hence, the correct answer is A...
kitannnnn 👍 1 Selected: A
ca = 11001010 inverted 7th bit = 11001000 = c8 ans = c801:b6ff:feb4:1
Ras_Al_Ghul 👍 1 Selected: A
convert 7th bit cA becomes c8 .
ekansh_m 👍 1 Selected: A
Correct answer is A. 7th bit of “a” is inverted to an 8

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Expert Analysis

Why the Answer Is Correct

A is correct. EUI-64 on R2's MAC: the first byte CA (1100 1010) flips its seventh bit to 1100 1000 = C8, so the interface ID starts with C801, and the FFFE insertion produces B6FF, yielding 2001:db8:9bb6:6bb9:C801:B6FF:FEB4:1.

Why the Other Options Are Wrong

B (C001) and C (C081) miss the seventh-bit inversion, so their first hextet is wrong. D does not follow the EUI-64 transformation.

Community Comment Notes

The vote is A (100). Commenters repeatedly note 'invert the 7th bit: CA becomes C8,' confirming C801:B6FF as the correct form.

Official Reference

https://learningnetwork.cisco.com/s/ccna-exam-topics

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