Which Subnet Mask Provides Six Usable IP Addresses?
A customer needs six usable IP addresses. Which of the following best meets this requirement?
Community Votes
77% of anonymous learners picked answer D. Votes are pick records left by other test-takers — they are not the verified answer.
Community Insight
This question tests the ability to calculate usable host counts and choose the smallest subnet that satisfies a requirement; the common trap is miscalculating the host count for /27, which actually provides 30 usable addresses, not 6.
For a customer needing six usable IP addresses, the best subnet mask among the options is 255.255.255.240 (/28), which yields 14 usable hosts. Community consensus supports option D as the most efficient choice, noting that an exact match would require a /29 subnet.
The most common wrong answer is C (255.255.255.224), selected by about 23% of voters, often because they mistakenly believe it provides exactly 6 usable IPs. In reality, /27 provides 30 usable addresses and wastes more addresses compared to /28.
Community Discussion (8 comments)
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Expert Analysis
Why the Answer Is Correct
Option D, 255.255.255.240 (/28), has 4 host bits, yielding 2^4 - 2 = 14 usable IP addresses. This is the smallest subnet listed that still meets the requirement of 6 usable addresses, minimizing wasted address space. As comment [1] notes, the ideal mask would be /29 (255.255.255.248) for exactly 6 usable addresses, but /28 is the next best option among those provided.Why the Other Options Are Wrong
Options A, B, and C all provide far more than needed: /25 gives 126 usable, /26 gives 62 usable, and /27 gives 30 usable. Comment [3] incorrectly claims /27 provides 6 usable addresses, but that is a miscalculation—/27 has 5 host bits, not 3. The question asks for the best fit, so larger subnets that waste more addresses are not the correct choice.Community Comment Notes
The consensus in the comments is clearly option D, with 77% of voters selecting it. Comment [5] emphasizes efficiency, pointing out that /28 provides enough addresses without wasting as many as /27. Comment [2] correctly calculates the /28 host count as 14. The minority who chose C appear to have misunderstood host-bit calculations or ignored the goal of minimizing wasted addresses.Official Reference
Exam Strategy
On subnetting questions, always determine the required number of usable hosts, then find the smallest subnet mask that provides at least that many usable addresses using the formula (2^n - 2). Remember that an exact option may not exist, so choose the one with the least waste while still covering the requirement.
Related Analysis
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