Electing the Root Bridge by Lowest Priority (SW2)
Refer to the exhibit. Which switch in this configuration will be elected as the root bridge? SW1 0С:E4:85:71:03:80 - SW2 0С:0E:1A:22:05:97 - SW3 0C:E0:A1:1A:3C:9D - SW4 0С:00:18:A1:B3:19 - 
Community Votes
100% of anonymous learners picked answer B. Votes are pick records left by other test-takers — they are not the verified answer.
Community Insight
When one switch has a strictly lower priority, it is root outright — MAC is only consulted on a priority tie.
STP elects the root by lowest bridge priority first. SW2's priority is 4096, lower than the other switches' priorities, so it becomes root without needing the MAC tiebreaker.
Picking the switch with the lowest MAC (e.g., SW4 0C:00:18...): priority is compared before MAC, and SW2's 4096 beats every other priority here.
Community Discussion (5 comments)
Comments & Corrections
No comments yet — spotted an error or have a note? Share it below.
Expert Analysis
Why the Answer Is Correct
B (SW2) is correct. SW2's bridge priority is 4096, the lowest in the exhibit, so it is elected root before any MAC comparison is needed.Why the Other Options Are Wrong
A (SW1), C (SW3), and D (SW4) all have higher priorities than SW2's 4096, so they cannot win the root election.Community Comment Notes
The vote is B (100). Commenters state SW2 has the lowest bridge priority (4096) and thus the lowest bridge ID.Official Reference
Related Analysis
Practice All 200-301 Questions
Access 220 questions with complete answers and detailed explanations.
View Full 200-301 Practice Test →