Root Bridge Election by Lowest MAC When Priorities Are Equal (SW4)

Answer Correct answer: D — All switches share the same bridge priority, so the lowest MAC elects the root; SW4 (0C:0A:05:22:05:97) is the lowest, making it root.

Refer to the exhibit. Which switch in this configuration will be elected as the root bridge? - image

  1. SW1: 0C:4A:82.:65:62:72
  2. SW2: 0C:0A:A8:1A:3C:9D
  3. SW3: 0C:0A:18:81:B3:19
  4. SW4: 0C:0A:05:22:05:97 Correct Answer

Community Votes

D
100%

100% of anonymous learners picked answer D. Votes are pick records left by other test-takers — they are not the verified answer.

Community Insight

When priorities are equal, the election is decided purely by the lowest MAC address — the classic reason an old switch with a small MAC can take over as root.

With identical bridge priorities across the switches, STP elects the root by the lowest MAC address. SW4's MAC (0C:0A:05:22:05:97) is the lowest of the four, so SW4 becomes the root bridge.

Picking SW3 or SW2 by reading the MACs out of order; compare byte-by-byte from the left — 0C:0A:05 is lower than 0C:0A:18 and 0C:0A:A8.

Community Discussion (4 comments)

vvk964278 👍 1 Selected: D
D is correct
exiledwl 👍 2
D) SW4 is correct, to determine root bridge first check lowest priority then lowest mac add
f2bdbb0 👍 3
the correct answer is sw 2
379c9f6 👍 2
correct

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Expert Analysis

Why the Answer Is Correct

D (SW4) is correct. Because every switch has the same bridge priority, the root is chosen by the lowest MAC address. SW4 (0C:0A:05:22:05:97) is lower than SW3 (0C:0A:18:81:B3:19), SW2 (0C:0A:A8:1A:3C:9D), and SW1 (0C:4A:82:65:62:72), so SW4 is root.

Why the Other Options Are Wrong

A (SW1), B (SW2), and C (SW3) all have higher MAC addresses than SW4 once priority is tied, so they cannot be root.

Community Comment Notes

The vote is D (100). Commenters confirm: first lowest priority, then lowest MAC, and SW4 has the lowest MAC.

Official Reference

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